Question

A bag contains 5 red balls, 8 white balls, 4 green balls and 7 black
balls. If one ball is drawn at random, find the probability that it is
(i) black
(ü) red
iii) not green​

Answer 1

Answer:

black=7/24

red=5/24

not green=20/24=5/6

Answer 2

Given,

5 red balls

8 white balls

4 green balls

7 black balls

total number of balls = 5+8+4+7 = 24

outcomes = red,white,green or black.

probability of getting a:

black =

$\frac{7}{24}$

red =

$\frac{5}{24}$

not green =

$\frac{5 + 8 + 7}{24} = \frac{20}{24} = \frac{5}{6}$

hope it helps

have a great day