Question

A bag contains 5 red balls and 7 blue balls. Two balls are drawn at random without replacement, and then find the probability of that one is red and other is blue.

Answer 1

Answer:

Step-by-step explanation: The total no. Of outcomes = 5 + 7 = 12.

The no. Of red balls = 5 P(R)

The no. Of blue balls = 7 P(B)

P(R) the probability the drawing a red ball = no of red balls / total no. Of outcomes.

=>5/12 .

P(B) is the probability of drawing a blue ball = no.of blue balls / total no. Of outcomes

=>7/12.

Answer 2

Answer:

0.265

Step-by-step explanation:

Total number of balls = 5 + 7 = 12

Number of red balls = 5

Number of blue balls = 7

Probability can be defined as the ratio of favorable outcomes to the total number of outcomes.

Probability of getting a  red ball is given by

$P(R)=\frac{5}{12}$

Now, the replacement is not allowed. Hence, total number of balls = 12-1 = 11

Hence, Probability of getting a  blue ball is given by

$P(B)=\frac{7}{11}$

Therefore, Probability of getting a  red ball and a blue ball is given by

$P(E)=P(R)\times P(B)\\\\=\frac{5}{12}\times\frac{7}{11}\\\\=\frac{35}{132}\\\\=0.265​$