A bag contains 5 red balls and 7 green balls .If one ball drawn from the bag a) what is the probability that it is a red ball? b) what is the probability that it is a green ball? c) what is the probability that it is a white ball?
Answers
Answered by
1
Answer:
White
6
Red
9
Green
Total number of balls =5+6+9
=20
(i) Probability =
Total cases
favourable cases
P(Green) =
20
9
(ii) P(White or red) =
20
5+6
=
20
11
(iii) P(neither green nor white) = P(Red)
=
20
6
=
10
3
Explation:
Mark me brainleast
Answered by
0
Answer:
given,
no.of red balls = 5
no.of green balls = 7
total no.of balls = 12
probability= no. of possible evets/ total no.of events
probability of red ball = 5/12
probability of green balls= 7/12
probability of white balls= 0/12= 12
I hope it helped u
Similar questions