A bag contains 5 red balls and some blue and yellow balls. If the probability of drawing a blue ball is thrice thatof a red ball and probability of getting a yellow ball is twice that of a blue ball, then find the probability of drawing 2balls at random such that at least one ball is blue
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Let number of blue balls in the bag =x
Total no of balls in bag =5+x [No. of redball =5]
Probability of drawing a blue ball =
Total no of ball
No. of blue ball
P(B)=
5+x
x
Probability of drawing a Red ball =
Total no of ball
No. of red ball
P(R)=
5+x
5
Given,
P(B)=2P(R)
5+x
x
=2(
5+x
5
)
x=10
Hence, no. of blue balls in the bag =10
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