Question

A bag contains 5 red balls and some blue balls, if the probability of drawing a blue ball is double that of a red ball, then find the number of blue balls in the bag.

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Answer 1

Answer:

$\pink{Let\:number \:of\: blue \:balls \:be \:x}$

$\red{Red \:balls \:are \:5.}$

$\lime{Total\: balls\: = \:5 \:+ \:x}$

$\green{Probability \:of \:blue\: ball \:= \:2\: × \:probability \:of \:red\: ball}$

$\blue{x\:/5\:+\:x \:= \:2 \:x \:5\:/\:5\:+\:x}$

$\yellow{x \:= \:10}$

$\cyan{Total \:blue \:balls \:are \:10}$

Answer 2

$\huge{\fcolorbox{cyan} {black} {\pink{Question}}}$

A bag contains 5 red balls and some blue balls, if the probability of drawing a blue ball is double that of a red ball, then find the number of blue balls in the bag.

$\huge{\fcolorbox{cyan} {black} {\pink{AnSwEr}}}$

$\pink{Let\:number \:of\: blue \:balls \:be \:x}$

$\red{Red \:balls \:are \:5.}$

$\lime{Total\: balls\: = \:5 \:+ \:x}$

$\green{Probability \:of \:blue\: ball \:= \:2\: × \:probability \:of \:red\: ball}$

$\blue{x\:/5\:+\:x \:= \:2 \:x \:5\:/\:5\:+\:x}$

$\yellow{x \:= \:10}$

$\cyan{Total \:blue \:balls \:are \:10}$

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