Question

A bag contains 5 red balls and some blue balls if the probability of drawing blue ball is double that of red ball then find the number of blue balls in the bag

Answer 1

Solution :

Let there be x blue balls in the bag.

∴ Total number of balls in the bag = 5 + x

Now,

          $p_{1}$ = Probability of drawning a blue ball = $\frac{x}{5 + x}$

          $p_{2}$ = Probability of drawing a red ball = $\frac{5}{5 + x}$

But it is given that $P_{1}$ = $2p_{2}$

⇒ $\frac{x}{5 + x}$ = $2 \times \frac{5}{5 + x}$

⇒ x = 10

Answer 2

Answer:

Solution :

Let there be x blue balls in the bag.

∴ Total number of balls in the bag = 5 + x

Now,

p_{1}p

1

= Probability of drawning a blue ball = \frac{x}{5 + x}

5+x

x

p_{2}p

2

= Probability of drawing a red ball = \frac{5}{5 + x}

5+x

5

But it is given that P_{1}P

1

= 2p_{2}2p

2

⇒ \frac{x}{5 + x}

5+x

x

= 2 \times \frac{5}{5 + x}2×

5+x

5

⇒ x = 10

Step-by-step explanation:

mark my answer as a brainlist answer