A bag contains 5 red smileys, 6 yellow smileys and 3 green smileys. If two smileys are picked at random, what is the probability that both are red or both are green in colour?
A) 7
B) 1/7
C) 3/7
D) 0
Answers
Answered by
0
ĀNSWĒR ⏬⏬
C.1/7
Given total number of smileys = 5 + 6 + 3 = 14
Now, required probability =
5C2/14C2 + 3C2/14C2
= 10/91 + 3/91
= 13/91
= 1/7
THANKS ✌✌
# NAVI ❤ HARYANVI ♠
C.1/7
Given total number of smileys = 5 + 6 + 3 = 14
Now, required probability =
5C2/14C2 + 3C2/14C2
= 10/91 + 3/91
= 13/91
= 1/7
THANKS ✌✌
# NAVI ❤ HARYANVI ♠
Answered by
0
A bag contains 5 red smileys, 6 yellow smileys and 3 green smileys. If two smileys are picked at random, what is the probability that both are red or both are green in colour?
A) 7
B) 1/7✔
C) 3/7
D) 0
ĀNSWĒR ⏬⏬
B)1/7
Explanation:
total number of smileys = 5 + 6 + 3 = 14
Now, required probability =
5C2/14C2 + 3C2/14C2
= 10/91 + 3/91
= 13/91 =1/7
THANKS ✌☺
#DÊSÎ ♥
A) 7
B) 1/7✔
C) 3/7
D) 0
ĀNSWĒR ⏬⏬
B)1/7
Explanation:
total number of smileys = 5 + 6 + 3 = 14
Now, required probability =
5C2/14C2 + 3C2/14C2
= 10/91 + 3/91
= 13/91 =1/7
THANKS ✌☺
#DÊSÎ ♥
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