Math, asked by nishajoshi1298, 1 year ago

A bag contains 5 while and 3 black balls. Two balls are drawn at random one after the other without replacement. Find the probability of drawing a black ball in the first second attempt respectively. Chp- probability.plz,plz,plz,plz answer

Answers

Answered by horrorhunter

HMM.
NICE QUESTION BUT HERE'S YOUR ANSWER

we know that probablity=no of event /total no of event
so probablity of getting a black ball will be
3/8

HOPE THIS WILL HELP YOU AND PLEASE MARK ME AS A BRAINLIST

IS IT THE RIGHT ONE

horrorhunter: so the answer was in the first attempt

horrorhunter: now in second attempt

horrorhunter: we know that one ball have been removed

nishajoshi1298: Thks

horrorhunter: now there are only 7 balls in the bag so our total event will be 7 now and the probablity in the second chance will be

horrorhunter: =2/7

horrorhunter: because there is only 2 black ball is left and total no. of ball left in the bag will be 7

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