A bag contains 5 white, 6 red and 4 green balls . What is probability of getting A. A GREEN BALL B. A WHITE BALL C. NON-RED BALL
desaishazi72:
S= 15 n( S) = 15 ... n( A) = a green balls ... n (A) = 4 .... n(B) = a white balls ...n(B)= 5 ... n(C) = non red ball .. n(C)= 9 ............. P (A) = n(A ) ÷ n(S)= 4÷ 15 and. P (B) = n( B) ÷ n(S) = 5 ÷ 15 = 1 /3 and. P(C) = n(C)/n(S)= 9 /15 = 3/5
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green ball=4by 15
white ball=5by 15
red ball = 6by 15
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