A bag contains 5 white and 3 black balls; another bag contains 4 white and 5 black balls. From any one of these bags a single draw of two balls is made. Find the probability that one of them would be white and other black
Answers
Answered by
9
bag1
no.of white balls=5
no.of black balls=3
p(white )=5÷8
p(black)=3÷8
bag 2
no.of white balls=4
no.of black balls=5
p(white balls)=4÷9
p(black )=5÷9
no.of white balls=5
no.of black balls=3
p(white )=5÷8
p(black)=3÷8
bag 2
no.of white balls=4
no.of black balls=5
p(white balls)=4÷9
p(black )=5÷9
natrog6604:
hii
Answered by
1
Bag 1
P(Black ball)=3/8
P(White ball)=5/8
Bag 2
P(Black ball)=5/9
P(white ball)=4/9
P(Black ball)=3/8
P(White ball)=5/8
Bag 2
P(Black ball)=5/9
P(white ball)=4/9
Similar questions