Question

A bag contains 5 white and 3 black balls; another beg contain 4 white and 5 black balls. from any one of these bags a single draw of two balls made. find the probability that one of them would be white and the other black ball.
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Answer 1

Step-by-step explanation:

The required probability is 14/17

Answer 2

Step-by-step explanation:

HEY MATE HERE IS YOUR ANSWER:

The probibility of getting whute balls from 1st bad and black from second bag.

$p(white) = \frac{total \: no \: of \: white \: balls}{total \: no \: of \: balls \: in \: bag} \\ p(white) = \frac{5}{8} \\ simillarly \\ p(black) = \frac{5}{9}$

The probability of getting white from second and black ball from first

$p(white) = \frac{4}{9} \\ p(black) = \frac{3}{8}$