Question

a bag contains 5 white and 3 black balls. Four balls are successively drawn out without replacement. What is the probability that they are alternately they are different colours?​

Answer 1

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5*3*4*2 =120, in same way as described above. So, there are 120+120 =240 expexted ways. Now, the total ways are taking the 4 balls randomly from total (5+3) = 8 balls, without replacement. Probability is 14.2% approximately.

Answer 2

Answer:

$\frac{1}{7}$

Step-by-step explanation:

it can be in two ways

W,B,W,B-----------eq 1

B,W,B,W-----------eq2

in first case,the probability=(5/8)X(3/7)X(4/6)X(2/5)=1/14

in second it is=(3/8)X(5/7)X(2/6)X(4/5)=1/14

so the probability that they are alternately they are different colors=1/14+1/14=1/7

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