Question

A bag contains 5 white and 4 red balls and a second bag contains 7 white and 3 red balls. If one ball is drawn at random from each bag, then find the probability that

() both are white;

(ii) both are red;

(iii) one white and one red.​

Answer 1

Answer:

let A be the event that both are white

and B be the event that white ball is drawn from each bag

pA)= 2/12

Answer 2

Answer:

Since, total no. of balls = 5+7+4+2 = 18

(i) No. of balls that are white or blue = 5+2 = 7

∴ Required probability =

18

7

(ii) No. of balls that are red or black = 7+4 = 11

∴ Required probability =

18

11

(iii) No. of balls that are not white = 7+4+2 = 13

∴ Required probability =

18

13

5=0.6990)

Explanation:

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