A bag contains 5 white balls 6 red balls and 9 Green balls A ball is drawn at random from the bag find the probability that the ball drawn is (I) a green ball (ii) a white or a red ball (iii) is neither a green ball nor a white ball.
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no. of green ball = 9
total no. of outcome = 20
(i) p(e) = 20/9
(ii)p(e) = white ball =5/20 =1/4
red ball = 6
p(e) =6/20=3/10
(iii) the probablity is 0
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