Question

A bag contains 50 p, 25 p and 10 p coins in the ratio 5: 9: 4, amounting to rs. 206. Find the number of coins of each type respectively.

Answer 1

Answer:

No. of 50p, 25p and 10p =5:9:4

let no.of 50p coin is 5x

No.of 25p coin is 9x

No.of 10p coin is 4x

Total amount =206

5x(0.5)+9x(0.25)+4x(0.1)=206

Therefore,

x=206/5.15 =40 coins

So no.of 50p coins = 5×40=200

No.of 25p coins = 9×40 =360

No.of 10p coins = 4×40=160

Total number of coins =200 +360+160=720

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