Question

A bag contains 50 p, 25 p and 10 p coins in the ratio 5: 9: 4, amounting to rs 206. Find the number of coins of 10 paise

Answer 1

50*5x+25*9x+10*4x=206
250x+225x+40x=206
515x =206
x=206/515


no.of 10 p=x*10

Answer 2

Answer:

160

Step-by-step explanation:

Let the number of 50 p, 25 p and 10p coins be 5y, 9y and 4y respectively. Then,

Value of 50 P coins = Rs. 5y x $\frac{50}{100}$ = Rs. $\frac{5y}{2}$.

Value of 25 P coins = Rs. 9y x $\frac{25}{100}$ = Rs. $\frac{9y}{4}$.

Value of 10 P coins = Rs. 4y x $\frac{10}{100}$ = Rs. $\frac{2y}{5}$.

Therefore, $\frac{5y}{2} + \frac{9y}{4} + \frac{2y}{5}$ = 206

50y + 45y + 8y = 4120 ---> 103x = 4120

x = $\frac{4120}{103}$ = 40

No. of 10 P coins = 4 x 40 = 160