Question

A bag contains 50 paise 25 paise and 10 paise coins in ratio 5:9:4 amounting to rs 206 find number of coins of each type respectively

Answer 1

(5*1/2+9*1/4+4*1/10)x=206
5/2+9/4+2/5)x=206
50+45+8/20)x=206
103)x=206*20
x=40
50 p coins=5*40=200
25 p coins=9*40=360
10 p coins= 40*4=160

Answer 2

Let the fixed ratio be x.

So number of 50 paise coins is 5x

number of 25 paise coins is 9x

number of 10 paise coin is 4x

Now,

Total value(in paise)=no. of 50 paise coins×5x +no. of 25 paise coins×9x + no. of 10 paise coins×4x. (why?)

So,

50(5x)+25(9x)+10(4x)=20600

250x+225x+40x=20600

515x=20600

.: x=20600/515=40

.:x=40

.:no. Of 50 paise coins=5x=5×40=200

.:No. Of 25 paise coins=9x=9×40=360

.: no. Of 10 paise coin=4x=4×40=160