Question

A bag contains 50 pause and 10 paise coins in ratio 5:9 amounting to 206... find the number of coins of each type

Answer 1

Hope u like my process
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Ratio of the coins = 5:9

Let the common ratio be x

So,

Total number of 50 paise = 5x

Total number of 10 paise = 9x

So,
Total 50 paise amounts to

$= \bf \:( 5x) \times 50 = rs \: \: 250x$

Total 10 paise amounts to

$= \bf \: (9x) \times 10 =rs \: \: 90x$

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By formula,
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=> 250x +90x = 2040

or, 340x = 2040

or, x = 2040/340 = 6

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So there are 30 coins of 50 paise

And

54 coins are of 10 paise.

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