Question

A bag contains 50 ps, 25 ps and 10 ps coins in the ratio 5: 9: 4, amounting to rs. 206. find the number of coins of each type.

Answer 1

$let \: 50p \: 25p \: 10p \: coins \: be \: 5x,9x,4x \\ now \: divide \: the \: number \: of \: coin \: relate \: to \: rupee \\ ( \frac{5x}{2}) + \frac{9x}{4}) + ( \frac{4x}{10} )= 206 \\ lcm \: of \: 2,4,5 \: is \: 20 \\ 50x \: + 45x \: + 8x \: = 206 \times 20 \\ 103x \: = 206 \times 20 \\ 103x \: = 4120 \\ x = \frac{4120}{103} \\ x = 40 \\ hence \: \\ 5x = 5 \times 40 = 200 \\ 9x = 9 \times 20 = 180 \\ 4x = 4 \times 20 = 80$

Answer 2

Answer:

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Step-by-step explanation:

A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.

A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.A) 360, 160, 200

A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.A) 360, 160, 200B) 160, 360, 200

A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.A) 360, 160, 200B) 160, 360, 200C) 200, 360,160 √

D) 200,160,300

D) 200,160,300Answer: C) 200, 360,160

Explanation :

let ratio be x.

let ratio be x.Hence no. of coins be 5x ,9x , 4x respectively

let ratio be x.Hence no. of coins be 5x ,9x , 4x respectivelyNow given total amount = Rs.206

let ratio be x.Hence no. of coins be 5x ,9x , 4x respectivelyNow given total amount = Rs.206=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206

let ratio be x.Hence no. of coins be 5x ,9x , 4x respectivelyNow given total amount = Rs.206=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206we get x = 40

let ratio be x.Hence no. of coins be 5x ,9x , 4x respectivelyNow given total amount = Rs.206=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206we get x = 40=> No. of 50p coins = 200

let ratio be x.Hence no. of coins be 5x ,9x , 4x respectivelyNow given total amount = Rs.206=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206we get x = 40=> No. of 50p coins = 200=> No. of 25p coins = 360

let ratio be x.Hence no. of coins be 5x ,9x , 4x respectivelyNow given total amount = Rs.206=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206we get x = 40=> No. of 50p coins = 200=> No. of 25p coins = 360=> No. of 10p coins = 160

SO ANSWER IS 200 , 360 , 160 .....

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