Question

A bag contains 50p, 25p and 10 paise coins in the ratio of 5 : 9 : 4 amounting to RS. 206. Find the number of coins of each type in that order.
a. 200,360,160
b. 360,160,200
c. 160,200,360
d. 100,210,320​

Answer 1

${EXPLANATION}$

Given :-

• A bag contains 50p coins, 25p coins , 10p coins  in ratio 5:9:4
• Total amount - 206Rs

To find:-

• No.of coins each type in that order

SOLUTION:-

• Total number of 50p coins  is 5x
• Total number of 25p coins  is 9x
• Total number of 10p coins  is 4x

Total value of 50p coins  is 50( 5x )

• Total value of 50p coins  is 250x

Total value of 25p coins is 25(9x )

• Total value of 25p coins  is 225x

Total value of 10p coins  is 10(4x )

• Total value of 10p coins is 40x

ATQ ,

250x+225x+40x= 206

515x = 206

515x = 206

x = 0.4 RS

x= 40 paise

So,

Total no.of 50p coins = 5x

= 5(40)

= 200

Total no.of 25p coins  = 9x

=9(40)

=360

Total no.of 10p coins = 4x

=4(40)

=160

So, the required answer is 200, 360,160 {a}