A bag contains 50p ,25p and 10p coin in the ratio 5:9:4 amounting to rupees 206 find the number of coming of each type
Answers
Answer:
Firstly multiply the ratio by respective coin value to get the ratio uniform (i.e in terms of rupees)you will get
(5*.5 : 9*.25 : 4*.10) = (2.5 : 2.25 : .40)
It gives the ratio of coins value ratio
So know according to question..
2.5x+2.25x+.40x = 206
5.15x = 206
x = 40
2.5*40 = 100 ( i.e the value of 50 paise coin)
So no. Of 50p coins 100/.5 = 200 coins
Similarly
Value of 25p coin will be 2.25*40=90 and no. Of 25p coin will be 90/.25 = 360
Value of 10p coins will be .40*40= 16 and no. Of 10p coin will be 16/.10 = 160
So the answer is 200(50p),360(25p)and 160(10p) coins are in the money bag.
Answer:
Step-by-step explanation:
50 p, 25 p, 10p, coins are in the ratio of 5:9:4
Let 50 coins =5x
25 p coins =9x
10 p coins =4x
Money in 50 p coins=₹ 5x×50/100=₹ 2.5x
Money in 25 p coins=₹ 9x×25/100=₹ 2.25x
Money in 10 p coins=₹ 4x×10/100=₹ 0.4x
Total money =₹ 2.5x+2.25x+0.4x=₹ 5.15x
Hence 5.15x=206
x=206/5.15=40
Hence 50 coins =5x=5×40=200
25 p coins =9x=9×40=360
10 p coins =4x=4×40=160