Question

a bag contains 50p 25p and 10p coin in the ratio 5:9:4 amount to the rs 206 find the number of coins of each type of respectively​

Answer 1

Answer:

• the number of 50p,25p and 10p coins in the purse are 200, 360 and 160 coins respectively

Step-by-step explanation:

Let the rational between the number of coins be y

Thus, the number of 50p, 25p and 10p coins will be 5y, 9y and 4y

Total value of 50 p coin = value of one coin × number of coins

= Rs 0.50 × 5y = Rs 2.50y

Similarly, total value of 25p coin

= Rs 0.25 × 9y = Rs 2.25y

And total value of 10p coins  

= Rs 0.10 × 4y = Rs 0.40y

Total values of all coins put together

= Rs (2.50y + 2.25y + 0.40y) = Rs 5.15y  

According to the statement, the total value of all coins is Rs 206

Hence, 5.15y = 206

y = 206/ 5.15

y = 40

The ratio of 50 p coin is 2.50y, thus

                     = 2.50 × 40= 100

The ratio of 25 p coin is 2.25y, thus

                     = 2.25 × 40 = 90

The ratio of 10 p coin is 0.40y, thus

                     = 0.40 × 40 = 16

Number of 50 p coin = 100/0.50 = 200 Nos.

Number of 25p coin = 90/0.25 = 360 Nos.

Number of 10p coin = 16 /0.10= 160 Nos

Answer 2

Answer:

10p coins=160

25p coins=360

50p coins=200

Step-by-step explanation:

let the no. of coins of 50p, 25p and 10p are 5x,9x,4x respectively

then

total amount of 10p coins=4x/10 rs

total amount of 50p coins=5x/2 rs

total amount of 25p coins=9x/4 rs

total amount=4x/10 rs+5x/2 rs+9x/4 rs

but given total amount=206 rs

so,

206=4x/10 +5x/2 +9x/4

206*20=8x+50x+45x

4120=103x

x=40

so no. of coins=

10p coins=160

25p coins=360

50p coins=200