Math, asked by zebaanzari273, 1 year ago

A bag contains 50p 25p and 10p coins in the ratio 5:9:4 amounting to rs 206. Find number of coins of each type

Answers

Answered by amayra14
5

Hey Mate!

Here's ur answer:

Solution:

Let the ratio be X.

Hence no. of coins be 5x , 9x and 4x.

Now given total amount= rs. 206

=> (.50×5x)+(.25×9x)+(.10×4x)=206

we get X=40.

=>No. of 50p coins=200

=>No. of 25p coins=360

=>No. of 10p coins=160

Ans. 200,360 and 160.

Plz mark as brainliest!!

Answered by kunduakash901
2

HEY!!!!!! MATE HERE'S THE SOLUTION TO YOUR QUESTION:

ATQ:-

let no. of 50p coins be 5x

let no. of 50p coins be 5xlet no. of 25p coins be 9x

let no. of 50p coins be 5xlet no. of 25p coins be 9xlet no. of 10p coins be 4x

50p= 0.5 Rs

25p= 0.25 Rs

10p= 0.1 Rs

Total sum= 206

so:-

(0.5×5x) + (0.25×9x) +(0.1×4x)= 206

2.5x + 2.25x + 0.4x = 206

5.15x = 206

so:- x = 40

therefore:-

no.of 50p coins= 200

no.of 50p coins= 200no. of 25p coins= 360

no.of 50p coins= 200no. of 25p coins= 360no. of 10p coins = 160

HOPE IT HELPS YOU........

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