A bag contains 50p 25p and 10p coins in the ratio 5:9:4 amounting to rs 206. Find number of coins of each type
Answers
Answered by
5
Hey Mate!
Here's ur answer:
Solution:
Let the ratio be X.
Hence no. of coins be 5x , 9x and 4x.
Now given total amount= rs. 206
=> (.50×5x)+(.25×9x)+(.10×4x)=206
we get X=40.
=>No. of 50p coins=200
=>No. of 25p coins=360
=>No. of 10p coins=160
Ans. 200,360 and 160.
Plz mark as brainliest!!
Answered by
2
HEY!!!!!! MATE HERE'S THE SOLUTION TO YOUR QUESTION:
ATQ:-
let no. of 50p coins be 5x
let no. of 50p coins be 5xlet no. of 25p coins be 9x
let no. of 50p coins be 5xlet no. of 25p coins be 9xlet no. of 10p coins be 4x
50p= 0.5 Rs
25p= 0.25 Rs
10p= 0.1 Rs
Total sum= 206
so:-
(0.5×5x) + (0.25×9x) +(0.1×4x)= 206
2.5x + 2.25x + 0.4x = 206
5.15x = 206
so:- x = 40
therefore:-
no.of 50p coins= 200
no.of 50p coins= 200no. of 25p coins= 360
no.of 50p coins= 200no. of 25p coins= 360no. of 10p coins = 160
HOPE IT HELPS YOU........
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