A bag contains 50p 25p and 10p coins in the ratio 5:9:4amounting to 206 find no of coins of each type
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Step-by-step explanation:
let the coins are 5x,9x and 4x
hence the sum of amount
=5x*50/100+9x*25/100+4x*10/100=206
5x/2+9x/4+2x/5=206
multiply by 20 we get
50x+45x+8x=206*20
103x=4120
x=4120/103=40
No of coins are
50p: 5x=5*40=200
25p: 9x=9*40=360
10p: 4x=4*40=160
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