Question

A bag contains 5ps coins, 10ps coins and 20ps coins in the ratio of 3:2:1. if their total value is rs. 11 what is the number of 5ps coins.

Answer 1

Let 'x' be the common part
Let 'a' be the number of 5ps coins
Let 'b' be the number of 10ps coins
Let 'c' be the number of 20ps coins
Given, a:b:c =3:2:1
Given, 5a+10b+20c =1100----------(1)
(I had converted 11 rupees into paise i.e 1 rs= 100 ps)
According to the ratio given, we can state that
a=3x, b=2x, c=x
Substitute values of a,b and c into equation(1)
=> 5(3x)+10(2x)+20x =1100
=> 15x+20x+20x =1100
=> 55x =1100
=> x =1100/55
=> x =20
The number of 5ps coins=a =3x =3(20) =60
Finally, the answer is 60
Hope it helps.