Question

A bag contains 6 1/4 kg of soil. Two-fifth of it was lost through a hole in the side. How much of it was lost?

Answer 1

SOLUTION :

GIVEN

$\displaystyle \sf{A \: bag \: contains \: \: 6 \: \frac{1}{4} \: kg \: of \: soil}$

$\displaystyle \sf{ \frac{2}{5} \: of \: it \: was \: lost \: through \: a \: hole \: in \: the \: side \: }$

TO DETERMINE

The amount of soil lost

EVALUATION

Here it is given that

$\displaystyle \sf{A \: bag \: contains \: \: 6 \: \frac{1}{4} \: kg \: of \: soil}$

Now

$\displaystyle \sf{6 \: \frac{1}{4} \: kg \: = \frac{25}{4} \: \: kg}$

Also it is given that

$\displaystyle \sf{ \frac{2}{5} \: of \: it \: was \: lost \: through \: a \: hole \: in \: the \: side \: }$

Hence the amount of soil lost

$\displaystyle \sf{{ = \frac{2}{5} \times \frac{25}{4} } \: \: kg}$

$\displaystyle \sf{{ = \frac{5}{2} \: \: kg}}$

$\displaystyle \sf{{ =2 \frac{1}{2} \: \: kg}}$

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LEARN MORE FROM BRAINLY

The angles of the triangle are

3x–40, x+20 and 2x–10

then the value of x is

(a) 40 (b) 35 (c) 50 (d) 45

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