Question

. A bag contains 6 blue balls , 2 white
balls and 4 orange balls . One ball is
drawn from the bag without looking into
the bag. Probability of getting either a
blue or orange ball is​

Answer 1

Answer:

possible outcomes = (6+2+4)=12

p(of getting either a blue or orange ball) = 10/12 =in simplified form 5/6

Explanation:

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Answer 2

Answer:

blue ball - 1/2

orange ball - 1/3

Explanation:

p(E) : no.of outcomes / total outcomes

blue= 6/6+2+4 = 6/12 = 1/2

orange= 4/6+2+4 = 4/12= 1/3