A bag contains 6 blue balls, 'x' red balls and 5 green balls. If two balls are picked randomly, then the probability of 1 being green and 1 being red is 9/38. Find the value of x.
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Answer:
9
explanpation.
total Balls : 11+x
1 green and 1 red can be done in two ways
first is green and second is Red or first is Red and second is Green.
( 5/ 11+x) . (x/ 10+x) + ( x/ ( 11+x).(5/ 10+X) = 9/38
solving above you get X=9
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