Question

A bag contains 6 green ,3 black,5 yellow and 2 blue balls.find the probability that a ball drawn at random is black or yellow

Answer 1

total number of balls in bag=6+3+5+2=16

probability of black ball P(B )=(3/16)

P(Y)=5/16

Answer 2

Answer:

$\text{P(a ball drawn at random is black or yellow)}=\frac{1}{2}$

Explanation:

A bag contains 6 green, 3 black, 2 blue and 5 yellow.

We need to find the probability that a ball drawn at random is black or yellow.

Let A be event to draw a black ball.

Let B be event to draw a yellow ball.

Total number of ball in a bag = 6 + 3 + 5 + 2 = 16

Favorable outcomes of event A = 3

Favorable outcomes of event B = 5

$\text{P(A)}=\frac{3}{16}$

$\text{P(B)}=\frac{5}{16}$

$\text{P(a ball drawn at random is black or yellow)}=\text{P(A)+P(B)}\Rightarrow \frac{3}{16}+\frac{5}{16}\Rightarrow \frac{8}{16}=\frac{1}{2}$

$\text{P(a ball drawn at random is black or yellow)}=\frac{1}{2}$