a bag contains 6 green and 4 white balls. two balls are drawn one by one without replacement. if the second ball drawn is white then what is the probability that the first ball drawn is also white?
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No. of balls = 6 + 4 = 10
If one is white then total = 10-1 = 9
Therefore remaining balls are 9
remaining white balls = 4-1 = 3
Probability of another ball be white = 3/9 = 1/3
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If one is white then total = 10-1 = 9
Therefore remaining balls are 9
remaining white balls = 4-1 = 3
Probability of another ball be white = 3/9 = 1/3
Hope this helps you
Plz mark this as brainlieast answer
Thanks
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