Question

A bag contains 6 green balls, some black balls and red balls.Number of black balls is as twice as the number of red balls. Probability of getting a green balls is thrice the probability of getting a red ball. Find 1) number of black balls 2) total number of balls. ​

Answer 1

Answer:

Step-by-step explanation:

Let the number of red balls be x

No. Of black ball is 2x.

Total balls= 6+x+ 2x=6+3x

Probability of getting green ball=6/(6+3x)

Probability of getting a red ball=x/(6+3x)

According to the given info,

6/(6+3x)=3*[x/(6+3x)]

On solving, x=2

1) no. Of black balls=2*2=4

2) total balls=6+3x= 6+3*2=6+6=12

HOPE IT HELPS

PLZZ MARK BRAINLIEST.....

Answer 2

Answer:

Let red balls be x and black balls be 2x

Total no. of balls is 6.

Probability of getting green balls is 6/(6+3x)

P of getting a red balls is x/(6+3x)

On solving it we get

x=2

So,

No. of black balls

2x = 2×2=4

Total no. of balls

6+3x=6+3×2=6+6=12.