Question

A bag contains 6 red 8 green balls. They are mixed thoroughly and one ball is drawn at rendom . find the probability of getting (1) a red ball (2) a green ball.​

Answer 1

Answer:

(1) option one..................................

Answer 2

Question :

A bag contains 6 red 8 green balls. They are mixed thoroughly and one ball is drawn at rendom .

To find the Probability :

• of red balls
• of green balls

Given :

• No. of red balls = 6
• No. of green balls = 8

SOLUTION 1 :

Total number of balls in the bag = 6 + 8 = 14

No . of red balls in the bag = 6

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$\sf{Probability=}\dfrac{No.~of~favourable~outcomes}{No.~of~possible~outcomes}$

Probability = $\sf\dfrac{\cancel6}{\cancel{14}^7}^{3}$

Probability = $\sf\dfrac{3}{7}$

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SOLUTION 2 :

Total number of balls in the bag = 6 + 8 = 14

No . of green balls in the bag = 8

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$\sf{Probability=}\dfrac{No.~of~favourable~outcomes}{No.~of~possible~outcomes}$

Probability = $\sf\dfrac{\cancel8}{\cancel{14}^7}^{4}$

Probability = $\sf\dfrac{4}{7}$

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Thus the Probability of getting :

Red balls = 3/7

Green balls = 4/7

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