Question

A bag contains 6 red and 4 green balls. a ball is drawn at random from bag. find probability that it is either red or green ball.

Answer 1

p(red)=6/10=3/5
p(green)=4/10=2/5

Answer 2

$\blue{Number \:of \: total \: possible \: outcomes} \\= Total \: number \:of \: balls \\= 6 + 4\\= 10$

$Number \:of \: red \:balls \: 6 , \: number \:of \\green \:balls \: 4$

$\orange {Number \: of \: favourable \: outcomes }\\= 6 + 4 \\= 10$

$\pink {P( red \:or \: green \:ball ) }\\\green {= \frac{Number \:of \: favourable \: outcomes }{Number \:of \: total \: possible \: outcomes } }\\= \frac{10}{10} \\= 1 \: \blue { ( Sure \:event )}$

Therefore.,

$\red{P( red \:or \: green \:ball )} \green {= 1 }$

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