Math, asked by hannahbean124, 10 months ago

A bag contains 6 red balls, 4 green balls, and 3 blue balls. If we choose a ball, then another ball without putting the first one back in the bag, what is the probability that the first ball will be green and the second will be red?

Answers

Answered by rajatking30
3

Answer:

Probability of first ball Will be green is 4/13.

Probability of second will be red is 6/12 that is equal to1/2

May it help you

Answered by gopalspdcl77
2

p(first ball)=4/13

p(second ball)=6/12=1/2

Step-by-step explanation:

p(first ball)=no.of green balls/total no.of balls

=4/13

one ball is removed then total no.of balls=12

p(second ball)=no.of red balls/total no.of balls

=6/12

=1/2

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