Question

a bag contains 6 red balls 8 white balls and 7 green balls a ball drawn from the bag out look into it. what was the probability to get white ball​

Answer 1

Step-by-step explanation:

A bag contains 6 red balls, 8 white balls, 5 green balls and 2 black balls. One ball is drawn at random from the bag. 

Then total number of balls in bag =6+8+5+2+1=22

Total number of out come =22

(i)The event is getting a  White ball=number of white ball in bag=8

Then  probability=228=114

(ii)The event getting the Red or black=The number of red & black ball in bag=6+8+1=9 (one ball is random)

The probability=229

(iii)The event getting the  Not green is total number of ball other then green ball=6+8+2+1=17

The probability=2217

(iv) The event getting the Neither white nor black=Total number of balls without white or black ball in bag=6+5=11

The probability=2211=21

Answer 2

Given :

• A bag contains 6 red balls , 8 white balls and 7 green balls .

To Find :

• Probability of getting a white ball .

Solution :

$\longmapsto\tt{No.\:of\:Red\:Balls=6}$

$\longmapsto\tt{No.\:of\:White\:Balls=8}$

$\longmapsto\tt{No.\:of\:Green\:Balls=7}$

$\longmapsto\tt{Total\:Balls=21}$

Now ,

$\longmapsto\tt{Favourable\:Outcomes=8}$

$\longmapsto\tt{Probability=\frac{No.\:of\:Fav.\:Outcomes}{Total\:No.\:of\:Outcomes}}$

$\longmapsto\tt\bf{\dfrac{8}{21}}$

So , The Probability of getting a White ball is 8/21 ...

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Probability :

It is defined as chances of occuring or happening of an event.

• Probability of an event can never be negative.
• Probability of an event always lies between 0 and 1.

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