Question

A bag contains 6 red balls and 8 blue balls. If two balls taken out from the bag, then find probability of getting
at most one blue ball?
1.67/91
2. 9/13
3. 69/91
4. 61/91
5. None of these​

Answer 1

Answer:

No. of red balls =n(R)=6

Let, no. of blue balls be x, n(B)=x

Total no. of balls in bag=n(T)=6+x

We know that, Probability P(Event) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

Probability of drawing a red ball, P(R)=

6+x

n(R)

Probability of drawing a blue ball, P(B)=

6+x

n(B)

Given,

Probability of drawing a blue ball from the bag is twice that of a red ball

i.e., P(B)=2×P(R)

6+x

n(B)

=2×

6+x

n(R)

x=2×6

n(B)=x=12

Total no. of balls in bag=n(T)=6+x=6+12=18.