Question

A bag contains 6 red balls and 8 green balls. 2 balls are drawn at random one by one with replacement. Find the probability that both the balls are green

Answer 1

Answer:

8/14 * 8/14

Step-by-step explanation:

Selecting a ball that has to be green is = 8/16

And its with replacement then we again have 8 green balls and 14 total

2nd ball is green is 8/16

Answer 2

Given:

A bag contains 6 red balls and 8 green balls. 2 balls are drawn at random one by one with replacement.

To Find:

Find the probability that both the balls are green

Solution:

Probability is defined as the chances for an event to happen out of all the possible outcomes for that event. It lies between 0 to 1 and is denoted by P.

The formula for probability is,

$P=\frac{Possible Outcomes}{TotalOutcomes}$

The probability for both the events 1st being green and 2nd being green will be multiplied together,

So the probability that 1st ball is green will be,

[tex]P=\frac{8}{14} \\ =\frac{4}{7} [/tex]

Now there is 13 balls left, and 7 green balls so the probability that 2nd is also green will be,

$P=\frac{7}{13}$

Now the probability that both is green will be,

[tex]P=\frac{4}{7} *\frac{7}{13} \\ =\frac{4}{13} [/tex]

Hence, the probability that both are green is 4/13.