Math, asked by vvma, 1 year ago

a bag contains 6 red balls and 8 green balls they are mixed thoroughly and one ball is drawn at random find the probability of getting a red ball b)a green ball

Answers

Answered by delroy

probability of getting red ball= number of red balls / total number of balls
= 6/(6+8)
=6/14
=3/7
probability of getting green ball= number of green balls / total number of balls
=8/(8+6)
=8/14
=4/7
on comparison the probability of getting a green ball is more than that of a red ball .
hope it helps!

vvma: yes it is wrong

sharoz: 1/8

sharoz: (a) 1/8

delroy: how

vvma: anpadh gavar

sharoz: (6/14×1/2)/6/14×1/2+8/4×1/2=1/8

delroy: please dont use slangs

delroy: but i think my answer is correct

sharoz: no

sharoz: solve by base therom

Answered by Tiara010109

Answer:

Step-by-step explanation:

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