A bag contains 6 red balls and some black balls. If the ratio of the probabilities of drawing a red ball to black is 3:4,find the (i) number of black balls (ii) probability of either a black ball
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red balls = 6
black balls = 8
i)8 balls
ii)8/14=4/7
hope 9t helps
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I think it is important to note here that the order in which balls are chosen does not matter.
The total number of ways of drawing 2 balls out of 7 is 7C2 i.e. 21
For first case we either draw 2 red (3C2) or 2 blue balls (4C2), for total favorable cases of 9
Hence probability of drawing same color balls is 921
The probability of drawing different color balls is therefore 1−921=1221
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