a bag contains 6 red balls and some blue balls. if the probability of drawing a blue ball from the bag is twice that of red ball, find the number of blue balls in the bag.
Answers
Answered by
39
No of red balls = 6
No. of blue balls = x (assumed value)
Total no. of balls = 6 + x
According to the question,
Probability of getting a red ball = 6/6+x
Probability of getting a blue ball = 2(6/6+x)
(As the probability of getting a blue ball is twice as much as the probability of getting a red ball. So 2 is multiplied.)
= 12/6+x
We know that 6 + x is the total no. of balls. So, 12 is the number of blue balls.
Hence, the total no of blue balls are 12.
Hope this helps you dear...
Plz mark my answer brainliest if you find it useful...
No. of blue balls = x (assumed value)
Total no. of balls = 6 + x
According to the question,
Probability of getting a red ball = 6/6+x
Probability of getting a blue ball = 2(6/6+x)
(As the probability of getting a blue ball is twice as much as the probability of getting a red ball. So 2 is multiplied.)
= 12/6+x
We know that 6 + x is the total no. of balls. So, 12 is the number of blue balls.
Hence, the total no of blue balls are 12.
Hope this helps you dear...
Plz mark my answer brainliest if you find it useful...
koushi49:
hi
Answered by
17
No of red balls = 6
No of blue balls = x
Total balls = x+6
Probability of getting a blue ball is double of getting a red ball
x / x+6 = 2( 6 / x+6)
x ( x +6 ) = 6(x+6) * 2
x^2 + 6x = 6x + 36 * 2
x^2 = 36 *2
x = √36 * 2
x = 6 * 2
x = 12
Similar questions