A bag contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans. If we choose a jelly bean, then another jelly bean without putting the first one back in the bag, what is the probability that the first jelly bean will be green and the second will be red?
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3
Step-by-step explanation:
green bean=4 red bean=6 blue bean=4 total=14
prob(green bean)=4/14=
prob(red)=6/14
Answered by
1
Answer:
probability that first one will be green is 2/7
probability that second one will be red is either 6-x/13 or 6/13not sure though
Step-by-step explanation:
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