A bag contains 6 red marbles, 5 blue marbles and 4 green marbles. If three marbles are drawn out of the bag, what is the exact probability that all three marbles drawn will be blue?
Answers
Answer:
Step-by-step explanation:
given a bag with
6Red
5Blue
4Green
total balls in the bag=6+4+5=15
taking three balls from a bag=15C3
but given that all the balls are of blue color
so all balls are blue=5C3
so probability=5C3/15C3
=(5!/3!*2!)/(15!/3!*12!)
=(5*4/2)/(15*14*13/6)
=10/(5*7*13)=10/455
=2/91
The probability is 2/91.
Given:
Total number of red marbles = 6
Total number of blue marbles = 5
Total number of green marbles = 4
To find:
The exact probability that all three marbles are drawn will be blue
Solution:
Total marbles -
= 6 + 5 + 4
= 15
Since there are 5 blue marbles, thus -
Probability of first marble to be blue = 5/15
Probability of second marble to be blue = 4/14
Probability of third marble to be blue = 3/13
Thus, probability will be -
= 5/15 × 4/14 × 3/13
= 1/3 × 2/7 × 3/13
= 2/91
Answer: The exact probability that all three marbles are drawn will be blue is 2/91
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