Question

A bag contains 6 red shirts,6 green shirts and 8 blue shirts two shirts are drawn randomly.What is the probality that at most one shirt is red .... answer is 27/38 ​

Answer 1

${\large{\mathfrak{\underline{\color{green}{† Given:-}}}}}$

A bag contains 6 red shirts,6 green shirts and 8 blue shirts two shirts are drawn randomly.

$\Large{\bf{\orange{\mathfrak{\dag{\underline{\underline{To \: Find:-}}}}}}}$

ToFind:−

Probability of a red shirt

$\Large{\bf{\red{\mathfrak{\dag{\underline{\underline{Solution:-}}}}}}}$

Solution:−

Number of red shirts = 6

Number of green shirts = 6

Number of blue shirts = 8

Probability of red shirt picked at randam =

Let R be an event for the probability of red shirt.

We know that,

$\boxed{\pink{\sf P(R) \: = \: \dfrac{Favourable \: outcomes \: for \: event \: R}{Total \: number \: of \: possible \: outcomes}}}$

P(R) = Total number of possible outcomes

Favourable outcomes for event

Here,

Favourable outcomes for event R = 6

Total number of possible outcomes = 6 + 6 + 8 = 20

Substituting the values,

$\sf P(R) \: = \: \dfrac{6}{20}P(R) = 206$

$\sf P(R) \: = \: \dfrac{\cancel{6}}{\cancel{20}}P(R) = 206$

$\sf P(R) \: = \: \dfrac{3}{10}P(R) = 103$

$\sf P(R) \: = \: 0.3P(R)=0.3$

Therefore,

$\underline{\boxed{\therefore{\purple{\tt{Probability \: of \: a \: red \: shirt \: = \: \dfrac{3}{10} \: or \: 0.3}}}}}$

∴ Probability of a red shirt = 103 or 0.3