A bag contains 6 white and 4 black balls. Two balls are drawn at random. The probability that they are of the same colour, is
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The Given condition would be satisfied if
1. Both the balls drawn are white2. Both the balls drawn are Black
Required Probability = P( Both the balls are white) + P(Both the balls are Black)
= 6/10 × 5/9 + 4/10×3/9 = 42/90 = 7/15
So, The Probability is 7/15
1. Both the balls drawn are white2. Both the balls drawn are Black
Required Probability = P( Both the balls are white) + P(Both the balls are Black)
= 6/10 × 5/9 + 4/10×3/9 = 42/90 = 7/15
So, The Probability is 7/15
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