A bag contains 6 white and 4 red balls. If a person draws 2 balls and receives 10 and 20 for a white and red balls respectively, then his expected amount is (a) 25 (b) 26 (c) 29 (d) 28
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A bag contains 6 white and 4 red balls.
A white ball drawn then Rs10
If red ball then Rs20
⇒ Expectation =2(n1P1 + n2P2)
Here P1
= Probability of getting a white ball= Rs.10
Here P2
= Probability of getting a red ball =Rs.20
∴ Expectation =2[0.6×10+0.4×20]
=Rs28.
Hence, the answer is Rs.28.
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