Question

A bag contains 6 white ball , 8 red balls and 2 blue balls . two balls are drawn at random. find the probability that atleast one ball is red ​
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Answer 1

Answer:

1/2 is the answer

Step-by-step explanation:

8/16 = 1/2

Answer 2

Answer:

23/30

Step-by-step explanation:

Probability of one red ball and one non red ball being drawn is,

p1 = 8C1*8C1/16C2

p1 = 8 * 8 / 120

p1 = 64/120

Probability of two red ball being drawn is,

p2 = 8C2/16C2

p2 = 28 / 120

Probability of atleast one red ball being drawn, p is

p = p1 + p2

p = 64/120 + 28/120

p = 92/120

p = 23/30

Alternatively you can also find this by calculating no red balls being drawn and subtract the answer from one.

p = 1 - p'

p' = 8C2 / 16C2

p' = 28 / 120

p = 1 - 28/120

p = 92/120

p = 23/30