A bag contains 7 blue, 5 red and 12 green balls Find the probability of obtaining a blue ball . If we draw a red ball and do not put it back into the bag ,what is the probability of obtaining a red ball and what is the probability of not obtaining a red ball?For your confusion answer of this question is 7/24,4/23,19/23
Answers
Answered by
34
probability of obtaining a blue ball =
p(E) =n(E) /n(s)
=total blue balls/total balls
=7/24
total no. of red balls=5
if we draw a red ball then red ball remain=4
and total no. of balls =23
then p(E) =4/23
probability for not obtaining red ball=
19/23
p(E) =n(E) /n(s)
=total blue balls/total balls
=7/24
total no. of red balls=5
if we draw a red ball then red ball remain=4
and total no. of balls =23
then p(E) =4/23
probability for not obtaining red ball=
19/23
Answered by
13
Answer:
=There are 7+5+12=24 balls
=Thus, total number of outcomes is=24
=There are 7 blue balls
=Thus,number of favourable outcomes for drawing a blue balls=7
=So, the probability that a blue ball is drawn=7/24=1/3
=Now, if red ball is drawn and not replaced, then the total number of balls in the box is 7+4+12=23
=Therefore, the probability of the drawing a red ball=4/23
=The probability of not obtaining a red ball=The probability of obtaining blue and green ball
=7/23 , 12/23
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