Question

A bag contains 7 blue, 5 red and 12 greenballs. Find the probability of obtaininga blue ball. If we draw a red ball and donot put it back into the bag, what is theprobability of obtaining a red ball and whatis the probability of not obtaining a red ball?
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Answer 1

Answer:

prob. of blue ball-7/24

prob. of red balls-5/24

prob. of all balls excepting red balls- 7+12-5/24= 14/24=7/12

Step-by-step explanation:

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Answer 2

Answer:

7/24, 4/23, 19/23

Step-by-step explanation:

Probability of obtaining a blue ball =

p(E) =n(E) /n(s)

= Total Blue balls / Total balls

= 7/24

Total no. of Red balls=5

If we draw a red ball then red ball remain=4

and Total no. of balls =23

then p(E) = 4/23

Probability for not obtaining red ball=

19/23