Question

A bag contains 7 blue, 8red,6 green and 5 yellow balls. Find the probability of getting
(a) a green ball
(b) a yellow ball
(c) a white ball

Answer 1

(a). probability of green ball = 6/26 = 3/13
(B) probability of yellow ball= 5/26
(c) probability of white ball= 0/26

Answer 2

blue=7
red=8
green=6
yellow=5
total number of trials=7+8+6+5=26
probability of green ball = 6
P(A)= 6/26
=3/13
probability of yellow ball= 5
P(A)=5/26
probability of white ball=0
P(A)=0/26
=0