A bag contains 7 blue balls,6 red balls and 2 yellow balls. Find the probability of each. a. Getting a red ball b. Getting a yellow ball
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A bag contain balls 7 blue,6 red,and 2 yellow
then sample space.
S= { 7,6,2 }
n(S)=15
Let event A be the red ball.
A= { 6 }
n(A)=6
p(A)= n(A)/n(S)
=6/15
=2/5
Let event B be the blue balls
B= { 7 }
n(B)= 7
p(B)= 7/15
Let event C be the yellow balls
C={2}
n(S)= 2
p(c)= 2/15
i hope understand you...
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